Find three consecutive odd numbers whose sum is 147.

To find three consecutive odd numbers whose sum is 147, let's represent the three consecutive odd numbers as \( x \), \( x+2 \), and \( x+4 \).

The sum of these three numbers is given by:

\[
x + (x+2) + (x+4) = 147
\]

Simplify the equation:

\[
3x + 6 = 147
\]

Subtract 6 from both sides:

\[
3x = 141
\]

Divide by 3:

\[
x = 47
\]

So, the three consecutive odd numbers are:

\[
47, 49, 51
\]

These three numbers add up to 147.

Would you like more details or have any questions?

Here are 5 related questions for further practice:
1. Find three consecutive even numbers whose sum is 132.
2. Find four consecutive odd numbers whose sum is 200.
3. Find three consecutive numbers whose sum is 108.
4. If the sum of three consecutive numbers is 75, what are the numbers?
5. Find three consecutive multiples of 3 whose sum is 99.

**Tip:** When dealing with consecutive numbers, you can represent them algebraically using a common variable and increments. This simplifies the process of solving the equations.

Discover how to find three consecutive odd numbers whose sum is 147 with a step-by-step solution. This problem involves algebraic representation of consecutive odd numbers and solving equations. Suitable for students in Grades 7-9.

Math Problem Statement

Solution

Ask a new question for Free

By Image

Math Problem Analysis

Mathematical Concepts

Formulas

Theorems

Suitable Grade Level

Related Recommendation