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The problem asks to find three consecutive integers that sum up to 93. 

Let the three consecutive integers be:
- \( x \) (the first integer),
- \( x+1 \) (the second integer),
- \( x+2 \) (the third integer).

The sum of these three integers is given by:

\[
x + (x + 1) + (x + 2) = 93
\]

Simplifying:

\[
3x + 3 = 93
\]

Now, subtract 3 from both sides:

\[
3x = 90
\]

Next, divide by 3:

\[
x = 30
\]

Thus, the three consecutive integers are:

\[
30, 31, 32
\]

Do you want more details or have any questions?

Here are some related questions you might find interesting:
1. What if the sum were 99 instead of 93? How would the integers change?
2. How do we handle finding four consecutive integers with a given sum?
3. How can we solve for consecutive even integers with a given sum?
4. How do we generalize this approach for any number of consecutive integers?
5. How do we solve the same problem if the integers are consecutive odd numbers?

**Tip:** When solving problems involving consecutive integers, always set up the variables so that their sum can be easily simplified (like using \( x, x+1, x+2 \) for three consecutive numbers).

Find three consecutive integers with a sum of 93.

Solve the problem of finding three consecutive integers whose sum equals 93. This detailed guide includes algebraic steps and solutions, perfect for students in Grades 6-8 learning about consecutive integers and basic algebraic equations.

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