https://file.aiquickdraw.com/mathbot/file/1726182757590keck4rxn.jpg

Let's solve the problem in the image. The task is to find three consecutive integers that sum to 48.

Let the three consecutive integers be represented as:
- \( x \) (the first integer),
- \( x+1 \) (the second integer),
- \( x+2 \) (the third integer).

Their sum can be written as:
\[
x + (x + 1) + (x + 2) = 48
\]

Simplify the equation:
\[
3x + 3 = 48
\]

Now, subtract 3 from both sides:
\[
3x = 45
\]

Finally, divide both sides by 3:
\[
x = 15
\]

So, the three consecutive integers are:
- First integer: \( x = 15 \),
- Second integer: \( x+1 = 16 \),
- Third integer: \( x+2 = 17 \).

Thus, the three consecutive integers are **15, 16, and 17**.

Do you have any questions, or would you like more details?

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Here are some related questions:
1. What are consecutive even integers that sum to 84?
2. How would the equation change if we were looking for four consecutive integers summing to 100?
3. Can consecutive odd integers also be used for such a problem? If so, what is the result for the sum of 72?
4. What are the three consecutive integers if their sum is 99?
5. How do you handle sums of consecutive integers where the total is negative?

**Tip:** When solving problems with consecutive integers, always form an equation with the first integer as \( x \) and express the others in terms of \( x \).

Find three consecutive integers with a sum of 48.

Learn how to solve the problem of finding three consecutive integers that sum to 48. This step-by-step solution breaks down the algebraic concepts behind the problem, suitable for students in Grades 6-8.

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