It seems there is some confusion in the expression you provided. The expression appears to be incomplete or ambiguous, but I'll try to clarify and interpret it based on possible meanings.

I think you meant:

$a_n = 2 - 2^n$

Where $a_n$ represents the nth term in the sequence. If that is correct, let's compute the 1st, 2nd, 3rd, and 10th terms:

1. First term (n = 1): $a_1 = 2 - 2^1 = 2 - 2 = 0$

2. Second term (n = 2): $a_2 = 2 - 2^2 = 2 - 4 = -2$

3. Third term (n = 3): $a_3 = 2 - 2^3 = 2 - 8 = -6$

4. Tenth term (n = 10): $a_{10} = 2 - 2^{10} = 2 - 1024 = -1022$

So, the first, second, third, and tenth terms in the sequence $2 - 2^n$ are:

$a_1 = 0, \quad a_2 = -2, \quad a_3 = -6, \quad a_{10} = -1022$

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Would you like further details or have any other questions?

Here are 5 related questions to explore:

1. What is the general formula for the nth term of this sequence?
2. How does the sequence behave as $n \to \infty$?
3. What is the sum of the first 10 terms of this sequence?
4. What happens if the power in the sequence was fractional instead of integer?
5. Can this sequence be expressed using a recurrence relation?

Tip: Always check how a sequence grows or shrinks by analyzing the general form of the nth term. This helps in understanding the long-term behavior of the sequence.