To find the correct value of $\tan(-110^\circ)$, follow these steps:

1. Step 1: Recognize the periodicity of the tangent function, which repeats every 180°. Hence: $\tan(-110^\circ) = \tan(180^\circ - 110^\circ) = \tan(70^\circ)$

2. Step 2: Determine the sign. Since the angle $-110^\circ$ lies in the third quadrant, the tangent function is positive in this quadrant.

3. Step 3: Now, find the tangent of $70^\circ$. Using a calculator: $\tan(70^\circ) \approx 2.747$

Therefore, $\tan(-110^\circ) \approx 2.747$.

Would you like more details or have any questions?

Here are 5 related questions to explore further:

1. What is the general formula for the tangent of negative angles?
2. How does tangent behave in each quadrant of the unit circle?
3. What is the value of $\tan(250^\circ)$?
4. How does the tangent function's periodicity help simplify angle calculations?
5. Can you find $\tan(290^\circ)$ using the same approach?

Tip: Always consider the quadrant of the angle when determining the sign of the trigonometric function!