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The image asks to "Find the supplement of \( 47^\circ 31' 49'' \)." It also instructs to round off the answer to two decimal places if necessary.

### Solution:
The supplement of an angle is calculated by subtracting the angle from \(180^\circ\).

Given angle:
\[ 47^\circ 31' 49'' \]

To find the supplement:
\[
180^\circ - 47^\circ 31' 49''
\]

Let's perform the subtraction:

1. **Seconds Subtraction:**
   \(0'' - 49'' = -49''\)  
   Since we can't have negative seconds, we borrow 1 minute (which is 60 seconds):
   \[
   60'' - 49'' = 11''
   \]
   Now we have \(179^\circ 59' 11''\).

2. **Minutes Subtraction:**
   \(59' - 31' = 28'\)

3. **Degrees Subtraction:**
   \(179^\circ - 47^\circ = 132^\circ\)

Thus, the supplement is:
\[
132^\circ 28' 11''
\]

In decimal form:
- \(11''\) can be converted to minutes: \(\frac{11}{60} = 0.1833'\)
- Total minutes: \(28' + 0.1833' = 28.1833'\)

Convert \(28.1833'\) to decimal degrees:
\[
\frac{28.1833}{60} \approx 0.4697^\circ
\]
So the final answer in degrees:
\[
132^\circ + 0.4697^\circ = 132.47^\circ
\]

**Final Answer:**
\[ \boxed{132.47^\circ} \]

Would you like more details on any part of the solution, or do you have any further questions?

### Related Questions:
1. What is the complement of \(47^\circ 31' 49''\)?
2. How do you convert angles from degrees, minutes, and seconds to decimal degrees?
3. How would you subtract angles if both had minutes and seconds?
4. What would be the supplement of \(132^\circ 28' 11''\)?
5. How do you find the supplement of an angle in radians?

### Tip:
When working with degrees, minutes, and seconds, always remember that 1 minute equals 60 seconds, and 1 degree equals 60 minutes. This conversion is crucial when borrowing during subtraction.

Find the supplement of 47° 31' 49''. Round off your answer to two decimal places if necessary.

Learn to find the supplement of the angle 47° 31' 49'' using the supplementary angle theorem. This guide covers key concepts in angle measurement and conversions between degrees, minutes, and seconds. Suitable for high school students in Grades 9-12.

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