Math Problem Statement

Locate all the relative maxima, relative minima, and saddle points; evaluate the iterated integrals; find the volume under the plane z = 2x + y and over a given rectangle.

Solution

Let's go through each question step-by-step to analyze and solve them.


Question 1

Problem: Locate all the relative maxima, relative minima, and saddle points for the function: f(x,y)=x2+xy2y2x+1.f(x, y) = x^2 + xy - 2y - 2x + 1.

Solution Steps:

  1. Compute the partial derivatives fxf_x and fyf_y.
  2. Set fx=0f_x = 0 and fy=0f_y = 0 to find the critical points.
  3. Use the second derivative test to classify each critical point:
    • Compute fxxf_{xx}, fyyf_{yy}, and fxyf_{xy}.
    • Determine the value of the discriminant D=fxxfyy(fxy)2D = f_{xx}f_{yy} - (f_{xy})^2 at each critical point.
    • Classify each point based on the value of DD and fxxf_{xx}.

Question 2

Problem: Evaluate the iterated integrals:

  1. 1224(2x2y+3xy2)dxdy\int_{-1}^2 \int_2^4 (2x^2y + 3xy^2) \, dx \, dy
  2. 0101x(xy+1)2dxdy\int_0^1 \int_0^1 \frac{x}{(xy + 1)^2} \, dx \, dy

Solution Steps:

  1. Evaluate the inner integral for each iterated integral.
  2. Substitute the result into the outer integral and evaluate it.

Question 3

Problem: Use a double integral to find the volume under the plane z=2x+yz = 2x + y over the rectangle R=(x,y):3x5,1y2R = (x, y) : 3 \leq x \leq 5, \, 1 \leq y \leq 2.

Solution Steps:

  1. Set up the double integral for the volume, which is given by: 3512(2x+y)dydx\int_{3}^{5} \int_{1}^{2} (2x + y) \, dy \, dx
  2. Evaluate the inner integral with respect to yy.
  3. Evaluate the resulting outer integral with respect to xx.

Would you like a detailed solution for each question? Here are some related questions you might consider:

  1. How do you determine saddle points for a given function?
  2. What is the significance of the discriminant in the second derivative test?
  3. How can we simplify iterated integrals with complex functions in the integrand?
  4. How does the region of integration affect the setup of a double integral for volume?
  5. Are there alternative methods to evaluate double integrals in terms of polar coordinates?

Tip: For the second derivative test, remember that if the discriminant D<0D < 0, it indicates a saddle point, where the function has neither a local max nor a min at that point.

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Math Problem Analysis

Mathematical Concepts

Calculus
Multivariable Calculus
Optimization
Iterated Integrals
Double Integrals

Formulas

First and second partial derivatives for critical points
Discriminant D = f_xx f_yy - (f_xy)^2 for the second derivative test
Double integral setup for volume calculation

Theorems

Second Derivative Test for Critical Points
Fundamental Theorem of Calculus for Multiple Integrals

Suitable Grade Level

Undergraduate Calculus