Math Problem Statement
- Given f(x) = 2x5 - 604-725x3 - 2875x2, find:
a) The values of a where f has a relative max or min.
b) The values of z on [0,30] where f takes on the absolute max or min. c) The values of where f has an inflection.
Solution
Given the function , we need to address the following points:
Step 1: Rewrite and Organize the Function
To simplify analysis, write in descending order of powers:
Part (a): Find Values of Where Has a Relative Maximum or Minimum
To locate relative maxima and minima, we find the critical points by calculating the derivative and setting it to zero.
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Compute the First Derivative :
-
Set :
Solve to find the critical points. This is a polynomial equation that can be solved numerically, as it may not have simple analytical solutions.
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Analyze the Critical Points: Evaluate the second derivative at these points to determine if they correspond to maxima or minima.
Part (b): Find Values of on Where Reaches Absolute Max or Min
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Evaluate at Critical Points in Found in Part (a).
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Evaluate at the Endpoints and :
- Find .
- Find .
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Compare Values: The absolute maximum and minimum on will be among the values found at the endpoints and the critical points in the interval.
Part (c): Find Points of Inflection
Points of inflection occur where the concavity of the function changes, which happens when the second derivative changes sign.
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Compute the Second Derivative :
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Set :
Solve to find potential points of inflection.
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Analyze for Sign Changes: Check intervals around these solutions to see if changes sign, indicating a change in concavity.
Summary of Results
- Relative Max/Min: Solve .
- Absolute Max/Min on : Evaluate at endpoints and critical points in the interval.
- Inflection Points: Solve and test for sign changes in .
Would you like the detailed solutions for each step or assistance with the calculations?
Follow-Up Questions
- How do you determine if a critical point is a maximum or minimum?
- What methods are available for solving polynomial equations?
- What is the difference between relative and absolute extrema?
- How can the second derivative test confirm points of inflection?
- Why do we check endpoints when finding absolute extrema on an interval?
Tip: In optimization problems, critical points in an interval are essential for identifying relative extrema.
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Math Problem Analysis
Mathematical Concepts
Calculus
Critical Points
Relative and Absolute Extrema
Inflection Points
Formulas
First Derivative: f'(x) = 10x^4 - 2175x^2 - 5750x - 604
Second Derivative: f''(x) = 40x^3 - 4350x - 5750
Theorems
First Derivative Test
Second Derivative Test
Suitable Grade Level
Undergraduate Calculus
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