Math Problem Statement

The perimeter of a rectangular garden is 43.8 feet. Its length is 12.4 feet. What is its width?

Solution

To solve the problem of finding the width of the rectangular garden, given the perimeter P=43.8ftP = 43.8 \, \text{ft} and the length L=12.4ftL = 12.4 \, \text{ft}, we can use the formula for the perimeter of a rectangle:

P=2L+2WP = 2L + 2W

Where:

  • LL is the length,
  • WW is the width.

Step-by-step solution:

  1. Substitute the given values into the perimeter equation:

43.8=2(12.4)+2W43.8 = 2(12.4) + 2W

  1. Simplify:

43.8=24.8+2W43.8 = 24.8 + 2W

  1. Subtract 24.8 from both sides to isolate the term with WW:

43.824.8=2W43.8 - 24.8 = 2W

19=2W19 = 2W

  1. Divide both sides by 2 to find WW:

W=192=9.5ftW = \frac{19}{2} = 9.5 \, \text{ft}

Conclusion:

The width of the garden is 9.5ft9.5 \, \text{ft}.

Would you like further details or have any questions?


Here are 5 related questions for further exploration:

  1. How do you calculate the area of the garden with the given dimensions?
  2. What would the perimeter be if the length increased by 5 feet?
  3. How does changing the width affect the perimeter of a rectangle?
  4. What are the possible dimensions if the perimeter stays the same but the width increases?
  5. Can you generalize the formula for the perimeter of other polygons?

Tip: Always double-check the values you substitute in a formula to avoid simple calculation errors.

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Math Problem Analysis

Mathematical Concepts

Algebra
Geometry

Formulas

Perimeter of a rectangle: P = 2L + 2W

Theorems

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Suitable Grade Level

Grades 6-8