Math Problem Statement

Solve

Solution

To solve this problem, let's first analyze the given information and the figure:

  1. Description of the Problem:

    • RTRT is a tangent to circle RR at point TT.
    • RT=6\overline{RT} = 6.
    • RC=4\overline{RC} = 4.
    • We need to find the ratio TRRC\frac{TR}{RC}.
  2. Understanding the Geometry:

    • RTRT being a tangent means it touches the circle at exactly one point, TT, which is on the circle.
    • RR is the center of the circle.
    • RCRC is a radius of the circle.
  3. Relevant Theorem:

    • The Power of a Point Theorem (also known as the Tangent-Secant Theorem) states that if a tangent from an external point intersects a secant that passes through the circle, the square of the length of the tangent segment equals the product of the lengths of the external and internal segments of the secant.

    In our scenario:

    • RT2=RCRBRT^2 = RC \cdot RB, where RBRB is the length of the secant line extending from RR to BB.
  4. Application to the Problem:

    • Using the information RT=6RT = 6 and RC=4RC = 4:

    RT2=RCRBRT^2 = RC \cdot RB

    62=4RB6^2 = 4 \cdot RB

    36=4RB36 = 4 \cdot RB

    RB=364=9RB = \frac{36}{4} = 9

  5. Find TRTR:

    • Since RTRT is a tangent and RCRC is a radius intersecting the tangent at TT, RTRT is perpendicular to RCRC at TT. Hence, we are dealing with a right-angled triangle RTCRTC where:

    RT=6andRC=4.RT = 6 \quad \text{and} \quad RC = 4.

    We use the Pythagorean theorem to find TRTR:

    TR2=RT2+RC2TR^2 = RT^2 + RC^2

    TR2=62+42TR^2 = 6^2 + 4^2

    TR2=36+16TR^2 = 36 + 16

    TR2=52TR^2 = 52

    TR=52=213TR = \sqrt{52} = 2\sqrt{13}

  6. Find the Ratio TRRC\frac{TR}{RC}:

    TRRC=2134=132\frac{TR}{RC} = \frac{2\sqrt{13}}{4} = \frac{\sqrt{13}}{2}

Therefore, the ratio TRRC\frac{TR}{RC} is 132\frac{\sqrt{13}}{2}.

Would you like more details on any part of this solution, or do you have any specific questions?

Related Questions:

  1. What is the Power of a Point theorem, and how is it derived?
  2. How does the Pythagorean theorem apply to circles and tangents?
  3. How do you prove that a tangent to a circle is perpendicular to the radius at the point of tangency?
  4. What are the properties of tangents to a circle from a common external point?
  5. How can we use geometric means to find the lengths of tangents from an external point to multiple circles?

Tip:

Always remember to verify if a given segment is a tangent to a circle. If it is, it will be perpendicular to the radius drawn to the point of tangency.

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Math Problem Analysis

Mathematical Concepts

Geometry
Circle Geometry
Pythagorean Theorem

Formulas

Pythagorean theorem

Theorems

Power of a Point Theorem
Pythagorean theorem

Suitable Grade Level

Grades 9-12