Math Problem Statement

Find the radius of this cone. What dimensions are given on this cone? What dimension are you trying to find? r = ? Area Label Arrowh = 12 volume = 16π V =
3 1 ​ πr 2 h

The volume and height are given. You're trying to find the radius . Good work! Start by substituting the volume and height in the equation. r = ? Area Label Arrowh = 12 volume = 16π V

3 1 ​ π r 2 h

16π

3 1 ​ · π · r 2 · 12 Great job! We can use the commutative property to multiply the factors in any order. It could be helpful to multiply
3 1 ​ and 12 first so that we can rewrite this expression with fewer terms. Rearrange the factors to show that we’re multiplying
3 1 ​ and 12 first, then multiplying by π times r 2 . r = ? Area Label Arrowh = 12 volume = 16π

16π

3 1 ​

· 12 · π · r 2

Great job! Multiply
3 1 ​ by 12 to rewrite the right side of the equation. r = ? Area Label Arrowh = 12 volume = 16π V

3 1 ​ πr 2 h

16π

3 1 ​ · π · r 2 · 12

16π

3 1 ​ · 12 · π · r 2

16π

· π · r 2

Good work! What is another way you can write 4 · π in the equation? r = ? Area Label Arrowh = 12 volume = 16π V

3 1 ​ πr 2 h

16π

3 1 ​ · π · r 2 · 12

16π

3 1 ​ · 12 · π · r 2

16π

4 · π · r 2

16π

4π · r 2

You got it! Next, what move can we make to get rid of 4π so that r 2 is alone on the right? r = ? Area Label Arrowh = 12 volume = 16π V

3 1 ​ πr 2 h

16π

3 1 ​ · π · r 2 · 12

16π

3 1 ​ · 12 · π · r 2

16π

4 · π · r 2

16π

4π · r 2

Divide both sides of the equation by 4π

Multiply both sides of the equation by 16

Divide both sides of the equation by r Excellent! You can divide both sides by 4π to get rid of 4π and get r 2 alone on the right side of the equation. Record dividing both sides by 4π in your equation work. r = ? Area Label Arrowh = 12 volume = 16π V

3 1 ​ πr 2 h

16π

3 1 ​ · π · r 2 · 12

16π

3 1 ​ · 12 · π · r 2

16π

4 · π · r 2

16π

4π · r 2

4π Good work! Now, divide both sides by 4π to get r 2 alone on the right side of the equation. r = ? Area Label Arrowh = 12 volume = 16π V

3 1 ​ πr 2 h

16π

3 1 ​ · π · r 2 · 12

16π

3 1 ​ · 12 · π · r 2

16π

4 · π · r 2

16π

4π · r 2

4π 4π

= Great job! You found the value of r 2 is 4. What is the value of r? r = ? Area Label Arrowh = 12 volume = 16π V

3 1 ​ πr 2 · h

16π

3 1 ​ · π · r 2 · 12

16π

3 1 ​ · 12 · π · r 2

16π

4 · π · r 2

16π

4π · r 2

4π 4π

4

r 2

= r

Solution

You're looking to find the radius rr of a cone, and you are given the following:

  • The height h=12h = 12
  • The volume V=16πV = 16\pi

Step-by-Step Solution:

The formula for the volume of a cone is:

V=13πr2hV = \frac{1}{3} \pi r^2 h

Substitute the known values for VV and hh:

16π=13πr21216\pi = \frac{1}{3} \pi r^2 \cdot 12

Next, simplify by multiplying 13\frac{1}{3} and 1212:

16π=4πr216\pi = 4\pi r^2

Now, divide both sides of the equation by 4π4\pi to isolate r2r^2:

16π4π=r2\frac{16\pi}{4\pi} = r^2

4=r24 = r^2

Finally, take the square root of both sides to solve for rr:

r=2r = 2

Conclusion:

The radius rr of the cone is 2.


Would you like more details on any part of the solution or have other questions? Here are some follow-up questions you might find useful:

  1. How does the formula for the volume of a cone relate to the geometry of the cone?
  2. What happens to the radius if the volume or height changes?
  3. How do we derive the formula for the volume of a cone from the formula for the volume of a cylinder?
  4. What is the surface area of a cone and how can we calculate it?
  5. How do the dimensions of a cone impact its volume?

Tip: When solving for variables in formulas involving pi, make sure to simplify the pi terms early to make the calculations easier.

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Math Problem Analysis

Mathematical Concepts

Geometry
Volume of a Cone
Algebra

Formulas

V = (1/3)πr^2h

Theorems

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Suitable Grade Level

Grades 7-9