Math Problem Statement

A company determines that its total profit is given by the function

Upper P left parenthesis x right parenthesis equals negative 2 x squared plus 402 x minus 4180.P(x)=−2x2+402x−4180.

The company makes a profit for those nonnegative values of x for which

Upper P left parenthesis x right parenthesis greater than 0.P(x)>0.

The company loses money for those nonnegative values of x for which

Upper P left parenthesis x right parenthesis less than 0.P(x)<0.

Find the values of x for which the company makes a profit and loses money.

Question content area bottom

Part 1

The company makes a profit on the interval

left parenthesis 11 comma 190 right parenthesis(11,190).

​(Type your answer in interval​ notation.)

Part 2

The company loses money on the interval

enter your response here.

​(Type your answer in interval​ notation.)

Solution

To find the intervals where the company makes a profit or loses money, we need to analyze the given quadratic profit function:

P(x)=2x2+402x4180P(x) = -2x^2 + 402x - 4180

Part 1: Finding when the company makes a profit

The company makes a profit when P(x)>0P(x) > 0. Since P(x)P(x) is a quadratic function (a parabola that opens downward due to the negative coefficient of x2x^2), we can solve for the values of xx by finding where P(x)=0P(x) = 0, which gives the boundaries of the interval where P(x)>0P(x) > 0.

  1. Set P(x)=0P(x) = 0 to find the roots: 2x2+402x4180=0-2x^2 + 402x - 4180 = 0

  2. Solve this quadratic equation using the quadratic formula: x=b±b24ac2ax = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} where a=2a = -2, b=402b = 402, and c=4180c = -4180.

    Substituting these values: x=402±40224(2)(4180)2(2)x = \frac{-402 \pm \sqrt{402^2 - 4(-2)(-4180)}}{2(-2)} x=402±161604334404x = \frac{-402 \pm \sqrt{161604 - 33440}}{-4} x=402±1281644x = \frac{-402 \pm \sqrt{128164}}{-4} x=402±357.924x = \frac{-402 \pm 357.92}{-4}

    Now, solve for both roots: x1=402+357.924=44.084=11.0211x_1 = \frac{-402 + 357.92}{-4} = \frac{-44.08}{-4} = 11.02 \approx 11 x2=402357.924=759.924=189.98190x_2 = \frac{-402 - 357.92}{-4} = \frac{-759.92}{-4} = 189.98 \approx 190

So, the roots are x1=11x_1 = 11 and x2=190x_2 = 190.

Since the parabola opens downward, the profit is positive between these two roots. Therefore, the company makes a profit for:

x(11,190)x \in (11, 190)

Part 2: Finding when the company loses money

The company loses money when P(x)<0P(x) < 0. This happens outside the interval where the company makes a profit, meaning for values of xx less than 11 and greater than 190.

Thus, the company loses money for:

x(,11)(190,)x \in (-\infty, 11) \cup (190, \infty)

Final Answer:

  • Profit Interval: (11,190)(11, 190)
  • Loss Interval: (,11)(190,)(-\infty, 11) \cup (190, \infty)

Would you like further clarification on solving quadratic equations, or more details on the intervals?

Here are 5 related questions:

  1. What are the general steps to solve a quadratic inequality like P(x)>0P(x) > 0?
  2. How does the shape of a parabola determine where the function is positive or negative?
  3. Can you explain how the discriminant helps determine the nature of the roots of a quadratic equation?
  4. How do you use interval notation to describe the solution to inequalities?
  5. What real-world applications might involve determining when a company makes a profit or loss?

Tip: Always check the direction the parabola opens (upward or downward) when interpreting the sign of the quadratic function in different intervals.

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Math Problem Analysis

Mathematical Concepts

Algebra
Quadratic Inequalities
Profit Functions

Formulas

Quadratic equation formula: x = [-b ± √(b² - 4ac)] / 2a
Profit function: P(x) = −2x^2 + 402x − 4180

Theorems

Quadratic Formula
Roots of Quadratic Functions
Sign of a Parabola

Suitable Grade Level

Grades 9-12