We know that Greg spent the exact same amount in both weeks. Here's how we can set up an equation to find the price of one pound of apples.

Let:

• $p$ = price of one pound of apples.

Week 1:

• Greg bought 2 pounds of apples.
• He spent $5.73 on cheese.
• The total amount he spent in Week 1 was: $2p + 5.73$

Week 2:

• Greg bought 5 pounds of apples.
• He spent $6.54 on cheese.
• The total amount he spent in Week 2 was: $5p + 6.54$

Since Greg spent the same amount both weeks, we can set the two expressions equal to each other:

$2p + 5.73 = 5p + 6.54$

Solving the equation:

1. Subtract $2p$ from both sides: $5.73 = 3p + 6.54$
2. Subtract 6.54 from both sides: $5.73 - 6.54 = 3p$ $-0.81 = 3p$
3. Divide both sides by 3: $p = \frac{-0.81}{3}$ $p = -0.27$

Thus, the price of one pound of apples is $0.27.

Would you like more details on any step?

Here are some related questions for further exploration:

1. How would the result change if Greg had bought 3 pounds of apples the second week?
2. What would be the total amount Greg spent on apples in the second week?
3. How much more did Greg spend on cheese the second week than the first?
4. How can we calculate the total cost of his snack over two weeks?
5. If the price of cheese increases by 10%, what would be the new total cost for each week?

Tip: Always align terms carefully when setting up equations to solve problems involving costs.