Math Problem Statement

The vector v has initial point P and terminal point Q. Find its position vector. That is, express v in the form ai + bj. P = (2, 3), Q = (9, 7).

Solution

The problem requires you to find the position vector v\mathbf{v} given the initial point P=(2,3)P = (2, 3) and the terminal point Q=(9,7)Q = (9, 7). To find the position vector:

v=QP=(x2x1,y2y1)\mathbf{v} = Q - P = (x_2 - x_1, y_2 - y_1)

Step-by-step solution:

  1. Subtract the corresponding xx-coordinates: x2x1=92=7x_2 - x_1 = 9 - 2 = 7

  2. Subtract the corresponding yy-coordinates: y2y1=73=4y_2 - y_1 = 7 - 3 = 4

Thus, the position vector v\mathbf{v} is: v=(7,4)\mathbf{v} = (7, 4)

Writing v\mathbf{v} in the form ai+bjai + bj:

v=7i+4j\mathbf{v} = 7i + 4j

This is your final answer.

Would you like further clarification or a deeper explanation?

Related Questions:

  1. What is a position vector, and why do we subtract the points in this order?
  2. How does the formula change if the coordinates of PP and QQ are reversed?
  3. Can you explain how position vectors are used in physics or geometry?
  4. How do you convert a position vector into magnitude and direction form?
  5. Can you determine the length (magnitude) of this vector? How?

Tip:

Always ensure you subtract the initial point's coordinates from the terminal point's coordinates to find the position vector correctly.

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Math Problem Analysis

Mathematical Concepts

Vector Geometry
Coordinate Subtraction
Position Vectors

Formulas

v = Q - P = (x2 - x1, y2 - y1)
Vector form: ai + bj

Theorems

Position Vector Theorem

Suitable Grade Level

Grade 9-11