We are asked to find the second coordinate (i.e., the y-component) of the displacement vector $\overrightarrow{PQ}$.

To calculate the displacement vector $\overrightarrow{PQ}$ from point $P(-3, 1)$ to point $Q(3, -2)$, we subtract the coordinates of $P$ from $Q$. The vector components are given by:

$\overrightarrow{PQ} = (x_Q - x_P, y_Q - y_P)$

Where:

• $x_P = -3$, $y_P = 1$
• $x_Q = 3$, $y_Q = -2$

So, the second (y-) coordinate of $\overrightarrow{PQ}$ is:

$y_Q - y_P = -2 - 1 = -3$

Thus, the second coordinate of $\overrightarrow{PQ}$ is $-3$.

Would you like further details or have any questions? Here are some related questions for practice:

1. What is the first (x-) coordinate of the displacement vector $\overrightarrow{PQ}$?
2. How do you find the magnitude of the vector $\overrightarrow{PQ}$?
3. What is the direction of the vector $\overrightarrow{PQ}$?
4. How can you represent the vector $\overrightarrow{PQ}$ in terms of its unit vector?
5. What are the properties of displacement vectors in general?

Tip: A displacement vector describes the change in position from one point to another. It's calculated by subtracting the initial point's coordinates from the final point's coordinates.