Math Problem Statement
Find a formula for the polynomial π(π₯) with degree 3 real coefficients zeros at π₯=1+4π and π₯=3 π¦-intercept at (0,204) π(π₯)=
Solution
To find the polynomial with the given properties, we will use the following information:
- Degree 3: The polynomial has a degree of 3, so it can be expressed in the form , where and are its roots.
- Real coefficients: The coefficients of the polynomial are real. If there is a complex root, its complex conjugate must also be a root.
- Zeros at and : The conjugate of , which is , must also be a root due to the real coefficients.
- -intercept at : This means .
Given this, the roots of the polynomial are , , and . The polynomial can be written as:
Step 1: Expand the Factors
First, we multiply the factors involving the complex roots:
Now, the polynomial becomes:
Step 2: Expand the Remaining Terms
Step 3: Determine Using the y-Intercept
Since the polynomial has a y-intercept of , we substitute and set :
Final Polynomial
Thus, the polynomial is:
Would you like a more detailed explanation or have any questions?
Questions
- What are complex conjugate roots, and why must they appear in polynomials with real coefficients?
- How do we determine the constant in a polynomial given a specific point?
- Why is it necessary to expand the polynomial when finding the final expression?
- How can we verify that the polynomial has the correct y-intercept?
- What is the significance of the degree of a polynomial?
- How does the Fundamental Theorem of Algebra relate to this problem?
- Can a polynomial with real coefficients have an odd number of non-real roots?
- How can you determine the end behavior of a polynomial function?
Tip
When dealing with polynomials, always check for complex conjugate pairs to ensure the coefficients remain real.
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Math Problem Analysis
Mathematical Concepts
Polynomials
Complex Numbers
Roots of Polynomials
Coefficient Realism
Formulas
Quadratic Formula
Cubic Polynomial Expansion
Theorems
Fundamental Theorem of Algebra
Suitable Grade Level
Grades 10-12
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