Math Problem Statement

Form a polynomial f(x) with real coefficients having the given degree and zeros. Degree 4; zeros: 3 + 3i; 3 multiplicity 2.

Solution

To form a polynomial f(x)f(x) with real coefficients given the specified degree and zeros, let's follow these steps based on the information provided:

Given Information:

  • Degree: 4
  • Zeros: 3+3i3 + 3i and 33 with multiplicity 2

Step 1: Understand Complex Conjugate Pairs

Since the polynomial has real coefficients, if 3+3i3 + 3i is a zero, then its complex conjugate 33i3 - 3i must also be a zero.

Step 2: List all Zeros

The zeros of the polynomial are:

  • 3+3i3 + 3i
  • 33i3 - 3i
  • 33 (with multiplicity 2)

Step 3: Form the Polynomial

The polynomial can be expressed as the product of factors corresponding to its zeros: f(x)=a(x(3+3i))(x(33i))(x3)2f(x) = a(x - (3 + 3i))(x - (3 - 3i))(x - 3)^2

Step 4: Multiply the Factors

  1. Multiply the complex conjugate factors: (x(3+3i))(x(33i))=(x33i)(x3+3i)(x - (3 + 3i))(x - (3 - 3i)) = (x - 3 - 3i)(x - 3 + 3i) This simplifies using the difference of squares formula: (x3)2(3i)2=(x3)2+9(x - 3)^2 - (3i)^2 = (x - 3)^2 + 9 Expanding (x3)2(x - 3)^2: (x3)2=x26x+9(x - 3)^2 = x^2 - 6x + 9 So, we have: (x3)2+9=x26x+9+9=x26x+18(x - 3)^2 + 9 = x^2 - 6x + 9 + 9 = x^2 - 6x + 18

  2. Now, combine this result with the other factor (x3)2(x - 3)^2: f(x)=a(x26x+18)(x3)2f(x) = a(x^2 - 6x + 18)(x - 3)^2

  3. Expand (x3)2(x - 3)^2 again: (x3)2=x26x+9(x - 3)^2 = x^2 - 6x + 9

  4. Multiply (x26x+18)(x26x+9)(x^2 - 6x + 18)(x^2 - 6x + 9) to get the expanded form: f(x)=a(x412x3+63x2108x+162)f(x) = a(x^4 - 12x^3 + 63x^2 - 108x + 162)

Final Answer

The polynomial f(x)f(x) in its expanded form is: f(x)=a(x412x3+63x2108x+162)f(x) = a(x^4 - 12x^3 + 63x^2 - 108x + 162)

Let me know if you would like more details or have any questions!

Relative Questions:

  1. How do you determine the conjugate of a complex number?
  2. What is the significance of the multiplicity of a root in a polynomial?
  3. How do you expand expressions using the distributive property?
  4. What is the difference between real and complex roots in a polynomial?
  5. How can the degree of a polynomial affect its possible number of roots?

Tip:

Always remember that if a polynomial has real coefficients, complex roots must come in conjugate pairs.

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Math Problem Analysis

Mathematical Concepts

Algebra
Polynomials
Complex Numbers

Formulas

Polynomial factorization: (x - root)
Difference of squares: (a - b)(a + b) = a^2 - b^2

Theorems

Complex Conjugate Root Theorem: Non-real roots of polynomials with real coefficients must occur in conjugate pairs

Suitable Grade Level

Grades 10-12