Math Problem Statement

Find a vector perpendicular to \(\begin{bmatrix} a \\ b \end{bmatrix}\).

Solution

To find a vector perpendicular to [ab]\begin{bmatrix} a \\ b \end{bmatrix}, you can switch the components and change the sign of one of them. If [ab]\begin{bmatrix} a \\ b \end{bmatrix} is a vector, a perpendicular vector is:

[ba]or[ba].\begin{bmatrix} -b \\ a \end{bmatrix} \quad \text{or} \quad \begin{bmatrix} b \\ -a \end{bmatrix}.

This works because the dot product between the two vectors will be zero, confirming they are perpendicular.

Would you like more details, or do you have any questions?

Here are some related questions to explore:

  1. How do you verify that two vectors are perpendicular?
  2. Why does switching components and changing the sign work to find a perpendicular vector in 2D?
  3. Can you generalize this method for vectors in 3D space?
  4. How can you find a vector perpendicular to two given vectors in 3D?
  5. What is the geometric significance of a perpendicular vector in vector fields?

Tip: For any vector [ab]\begin{bmatrix} a \\ b \end{bmatrix}, perpendicular vectors ensure the dot product equals zero.

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Linear Algebra
Vector Operations
Perpendicular Vectors

Formulas

Dot product of perpendicular vectors equals zero

Theorems

Dot Product Theorem for Perpendicularity

Suitable Grade Level

Grade 10-12