Math Problem Statement

What is the perimeter of a quadrilateral with sides given by the expressions 2y, y, 2y + 7, and y + 3?

Solution

The problem asks for the perimeter of a quadrilateral with sides given by the following expressions:
2y2y, yy, 2y+72y + 7, and y+3y + 3.

The perimeter PP of the quadrilateral is the sum of all the sides:

P=(2y)+(y)+(2y+7)+(y+3)P = (2y) + (y) + (2y + 7) + (y + 3)

Now, let's simplify:

P=2y+y+2y+7+y+3P = 2y + y + 2y + 7 + y + 3 P=(2y+y+2y+y)+(7+3)P = (2y + y + 2y + y) + (7 + 3) P=6y+10P = 6y + 10

Thus, the perimeter of the quadrilateral is 6y+106y + 10.

The correct answer is: 6y + 10.

Would you like more details, or do you have any other questions? Here are some related questions you might find helpful:

  1. How do you find the perimeter of different polygons?
  2. How does simplifying algebraic expressions work?
  3. What are the properties of a quadrilateral?
  4. How can you solve for yy if given the value of the perimeter?
  5. What is the difference between perimeter and area in geometry?

Tip: Always remember to combine like terms when simplifying expressions!

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Math Problem Analysis

Mathematical Concepts

Algebra
Perimeter
Quadrilaterals
Simplifying Expressions

Formulas

Perimeter of quadrilateral = sum of all sides

Theorems

Addition of like terms

Suitable Grade Level

Grades 6-8