Math Problem Statement

Kenzo works out that the HCF of two numbers is 2232= 36. What two numbers might Kenzo have been using?2^2\cdot3^2=\text{ }36.\text{ What two numbers might Kenzo have been using?}

Solution

Given that the Highest Common Factor (HCF) of two numbers is 2232=362^2 \cdot 3^2 = 36, let's break down the problem to find potential pairs of numbers.

  1. HCF Breakdown: The HCF tells us that both numbers share the prime factors 222^2 and 323^2. This means each number must include at least 222^2 and 323^2 in their prime factorizations.

  2. Prime Factor Constraints: Each number must have a form that includes 22×32×(additional primes and/or higher powers)2^2 \times 3^2 \times (\text{additional primes and/or higher powers}). Let's express these numbers in general forms: a=22×32×m,b=22×32×n,a = 2^2 \times 3^2 \times m, \quad b = 2^2 \times 3^2 \times n, where mm and nn are coprime integers (they do not share any common prime factors). The HCF of aa and bb will then be 22×32=362^2 \times 3^2 = 36.

  3. Examples of Possible Pairs: To keep things simple, we can choose small values for mm and nn. Here are a couple of examples:

    • If m=1m = 1 and n=5n = 5: a=22×32×1=36,b=22×32×5=180.a = 2^2 \times 3^2 \times 1 = 36, \quad b = 2^2 \times 3^2 \times 5 = 180. Therefore, one possible pair is (36,180)(36, 180).
    • If m=2m = 2 and n=3n = 3: a=22×32×2=72,b=22×32×3=108.a = 2^2 \times 3^2 \times 2 = 72, \quad b = 2^2 \times 3^2 \times 3 = 108. Another possible pair is (72,108)(72, 108).
  4. General Observation: There are infinitely many pairs of numbers whose HCF is 3636. They can generally be expressed as: (22×32×m,22×32×n),(2^2 \times 3^2 \times m, 2^2 \times 3^2 \times n), where mm and nn are coprime.

Do you want more details or have any questions?

Here are 5 related questions that expand on this topic:

  1. How would you find the HCF of more than two numbers?
  2. If the HCF of two numbers is 3636 and their LCM is 10801080, what are the numbers?
  3. What is the difference between the HCF and the least common multiple (LCM) of two numbers?
  4. Can two numbers have an HCF greater than one if one of the numbers is a prime number?
  5. How would the process change if the HCF was a different number, say 1818 instead of 3636?

Tip: To find possible pairs of numbers with a given HCF, ensure both numbers' prime factorizations include the given HCF, and explore different coprime multipliers for flexibility in choosing pairs.

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Math Problem Analysis

Mathematical Concepts

Number Theory
Prime Factorization
Highest Common Factor (HCF)

Formulas

HCF(a, b) = Product of common prime factors

Theorems

Fundamental Theorem of Arithmetic

Suitable Grade Level

Grades 8-10