Math Problem Statement

How would I solve this problem? do not solve the problem, only show me the steps

A random variable X has PMF p(X = k) = a / [k(k+1)] for k = 1, 2, ..., 4, where a is a constant. Then, what is the value of p(1 ≤ X ≤ 3)? Round to 3 decimal places.

Solution

To solve this problem, where you are asked to find p(1X3)p(1 \leq X \leq 3), follow these steps:

Step 1: Identify the Probability Mass Function (PMF)

You are given the PMF for the random variable XX: p(X=k)=ak(k+1),k=1,2,3,4p(X = k) = \frac{a}{k(k+1)}, \quad k = 1, 2, 3, 4 where aa is a constant.

Step 2: Find the Range of Interest

You are asked to compute the probability that XX is between 1 and 3, inclusive: p(1X3)=p(X=1)+p(X=2)+p(X=3)p(1 \leq X \leq 3) = p(X = 1) + p(X = 2) + p(X = 3) This means you will sum the probabilities of XX being equal to 1, 2, and 3 using the given PMF formula.

Step 3: Compute Each Individual Probability

For each k=1,2,3k = 1, 2, 3, calculate the probability: p(X=k)=ak(k+1)p(X = k) = \frac{a}{k(k+1)} Substitute k=1,2,3k = 1, 2, 3 into the PMF formula to find:

  • p(X=1)p(X = 1)
  • p(X=2)p(X = 2)
  • p(X=3)p(X = 3)

Step 4: Normalize the PMF

Since the total probability must sum to 1, use the fact that: p(X=1)+p(X=2)+p(X=3)+p(X=4)=1p(X = 1) + p(X = 2) + p(X = 3) + p(X = 4) = 1 This equation allows you to solve for the constant aa.

Step 5: Calculate the Final Probability

Once you have the value of aa, use it to calculate p(1X3)p(1 \leq X \leq 3).


Let me know if you would like further clarifications or want to proceed with specific parts of the solution!

Here are 5 follow-up questions:

  1. How is the constant aa determined in a probability mass function?
  2. Why does the sum of all probabilities for a discrete random variable equal 1?
  3. What are the conditions for a function to be a valid probability mass function (PMF)?
  4. Can you extend this method to find probabilities for different ranges of XX?
  5. How does the PMF change if the range of kk increases?

Tip: When solving for a constant in probability problems, always check the total probability constraint p(X=k)=1\sum p(X=k) = 1.

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Math Problem Analysis

Mathematical Concepts

Probability
Discrete Random Variables
Probability Mass Function (PMF)

Formulas

p(X = k) = a / [k(k+1)]
p(1 ≤ X ≤ 3) = p(X=1) + p(X=2) + p(X=3)
Sum of probabilities for a PMF: p(X=1) + p(X=2) + p(X=3) + p(X=4) = 1

Theorems

Total probability must equal 1 for a discrete random variable

Suitable Grade Level

Grades 10-12