Math Problem Statement

Find specific terms in arithmetic sequences, such as the 21st term of the sequence 18, 14, 10,... and others.

Solution

The image contains four problems related to arithmetic or geometric sequences. Let’s break them down one by one.


Problem e:

Find the 21st term of the sequence 18, 14, 10, ...

This is an arithmetic sequence where:

  • First term a1=18a_1 = 18
  • Common difference d=1418=4d = 14 - 18 = -4

The formula for the nn-th term of an arithmetic sequence is: an=a1+(n1)da_n = a_1 + (n - 1) \cdot d For the 21st term (n=21n = 21): a21=18+(211)(4)=18+20(4)=1880=62a_{21} = 18 + (21 - 1) \cdot (-4) = 18 + 20 \cdot (-4) = 18 - 80 = -62

So, the 21st term is -62.


Problem f:

Find the 19th term of the sequence 32,72,112,3\sqrt{2}, 7\sqrt{2}, 11\sqrt{2}, \dots

This is an arithmetic sequence where:

  • First term a1=32a_1 = 3\sqrt{2}
  • Common difference d=7232=42d = 7\sqrt{2} - 3\sqrt{2} = 4\sqrt{2}

Using the formula for the nn-th term of an arithmetic sequence: an=a1+(n1)da_n = a_1 + (n - 1) \cdot d For the 19th term (n=19n = 19): a19=32+(191)42=32+1842=32+722=752a_{19} = 3\sqrt{2} + (19 - 1) \cdot 4\sqrt{2} = 3\sqrt{2} + 18 \cdot 4\sqrt{2} = 3\sqrt{2} + 72\sqrt{2} = 75\sqrt{2}

So, the 19th term is 75√2.


Problem g:

Find the 30th term of the sequence 13,1,123,\frac{1}{3}, 1, 1\frac{2}{3}, \dots

This is an arithmetic sequence where:

  • First term a1=13a_1 = \frac{1}{3}
  • The common difference d=113=23d = 1 - \frac{1}{3} = \frac{2}{3}

Using the formula for the nn-th term of an arithmetic sequence: an=a1+(n1)da_n = a_1 + (n - 1) \cdot d For the 30th term (n=30n = 30): a30=13+(301)23=13+2923=13+583=593=1923a_{30} = \frac{1}{3} + (30 - 1) \cdot \frac{2}{3} = \frac{1}{3} + 29 \cdot \frac{2}{3} = \frac{1}{3} + \frac{58}{3} = \frac{59}{3} = 19 \frac{2}{3}

So, the 30th term is 19⅔.


Problem h:

Find the nn-th term of the sequence 2, 5, 8, ...

This is an arithmetic sequence where:

  • First term a1=2a_1 = 2
  • Common difference d=52=3d = 5 - 2 = 3

Using the formula for the nn-th term of an arithmetic sequence: an=a1+(n1)da_n = a_1 + (n - 1) \cdot d Thus, the formula for the nn-th term is: an=2+(n1)3=2+3n3=3n1a_n = 2 + (n - 1) \cdot 3 = 2 + 3n - 3 = 3n - 1

So, the nn-th term is 3n13n - 1.


Let me know if you'd like further clarifications or more details!

Here are five related questions to expand your knowledge:

  1. How can you derive the general formula for a geometric sequence?
  2. What are the differences between arithmetic and geometric sequences?
  3. How do you find the sum of the first nn terms in an arithmetic sequence?
  4. What changes when the common difference of a sequence is negative?
  5. Can an arithmetic sequence have irrational numbers as terms?

Tip: Always check the common difference (or ratio for geometric sequences) to ensure correct identification of the sequence type.

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Math Problem Analysis

Mathematical Concepts

Arithmetic Sequences
Algebra

Formulas

nth term of arithmetic sequence: a_n = a_1 + (n - 1) * d

Theorems

Arithmetic Sequence Formula

Suitable Grade Level

Grades 10-12