Math Problem Statement
Solution
Let's analyze the problem from the uploaded image:
We are tasked with finding the missing dimension (a binomial) for the rectangular prism on the right, given that both prisms have the same volume.
Step 1: Volume of the Hexagonal Prism (Left Prism)
The volume of the left prism is calculated as:
Base Area of the Hexagonal Prism:
The base of the hexagonal prism consists of a regular hexagon divided into six equilateral triangles.
Each equilateral triangle has a side length of and an area formula:
So, the total area of the hexagon is:
Height of the Hexagonal Prism:
The height is given as .
Total Volume of the Hexagonal Prism:
Step 2: Volume of the Rectangular Prism (Right Prism)
The volume of the rectangular prism is also given as:
Base Area of the Rectangular Prism:
The base area is:
Total Volume of the Rectangular Prism:
The height of the rectangular prism is unknown, represented as . Let this height be . Then:
Step 3: Equating the Volumes
Since the volumes of both prisms are equal:
Solve for :
Step 4: Representing the Missing Dimension
The missing height of the rectangular prism is:
Would you like a detailed explanation of any of the steps or further simplification? 😊
Related Questions:
- How is the volume of a hexagonal prism derived in general?
- Why does the base of a hexagonal prism consist of six equilateral triangles?
- What is the relationship between the area of a hexagon and its side length?
- How would the solution change if one of the -values were different?
- Could you calculate the exact numerical value of the missing height for ?
Tip:
Always verify that units and terms cancel correctly when equating expressions—this ensures your algebraic manipulations are valid.
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Math Problem Analysis
Mathematical Concepts
Volume of Prisms
Equating Volumes
Simplification of Expressions
Formulas
Volume = Base Area × Height
Area of a Hexagon = 6 × (√3/4) × side^2
Volume of Hexagonal Prism = Base Area × Height
Volume of Rectangular Prism = Base Area × Height
Theorems
Equating Volumes of Solids
Suitable Grade Level
Grades 10-12
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