To find the value of $x$ in the triangle, we can use the fact that the sum of the interior angles of any triangle is always $180^\circ$.

Given:

• One angle is $61^\circ$,
• Another angle is $41^\circ$,
• The third angle is $x^\circ$.

We can set up the equation: $x + 61^\circ + 41^\circ = 180^\circ$

Simplifying: $x + 102^\circ = 180^\circ$

Now, solve for $x$: $x = 180^\circ - 102^\circ = 78^\circ$

Thus, the value of $x$ is $78^\circ$.

Would you like more details or have any questions? Here are some related questions you could explore:

1. How do you calculate the sum of angles in a polygon?
2. What is the exterior angle theorem in triangles?
3. How does the Pythagorean theorem apply in right triangles?
4. How would this change if the triangle were not a standard triangle but an isosceles one?
5. Can you prove that the sum of the interior angles of any triangle is always 180°?

Tip: Always double-check the sum of angles when solving triangle problems to ensure they add up to 180°.