Math Problem Statement

Find the value of x in a triangle where the angles are given as 92°, 41°, and x°.

Solution

To find the value of xx in this triangle, we can use the fact that the sum of the interior angles in any triangle is 180180^\circ.

The angles given are:

  1. 9292^\circ
  2. 4141^\circ
  3. xx^\circ

Using the triangle angle sum property: x+92+41=180x + 92^\circ + 41^\circ = 180^\circ

Now, combine the known angles: x+133=180x + 133^\circ = 180^\circ

Subtract 133133^\circ from both sides to solve for xx: x=180133x = 180^\circ - 133^\circ x=47x = 47^\circ

Answer:

x=47x = 47^\circ

Would you like more details, or do you have any questions?

Here are some related questions:

  1. What is the sum of angles in a quadrilateral?
  2. How would the calculation change if the triangle had an obtuse angle?
  3. What properties define an isosceles triangle?
  4. How can we determine if a triangle is acute, right, or obtuse by its angles?
  5. How do angle sums help in real-world applications like architecture?

Tip: Remember, the sum of angles in any triangle is always 180180^\circ.

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Math Problem Analysis

Mathematical Concepts

Geometry
Angle Sum Property in Triangles

Formulas

Sum of interior angles in a triangle: x + y + z = 180°

Theorems

Triangle Angle Sum Theorem

Suitable Grade Level

Grades 6-8