Math Problem Statement

A and B two solutions containing milk nd water. Solution A has 10% milk and B has X% milk. Both are mixed in ratio 3:2 to form a solution C . Then A and C are mixed in equal quantities then milk in resultant solution is 12.5% find X

Solution

Let's work through the problem step by step to find the value of XX, which represents the percentage of milk in solution B.

Step 1: Understand the problem

  • Solution A has 10% milk.
  • Solution B has X%X\% milk.
  • Solutions A and B are mixed in a ratio of 3:2 to form Solution C.
  • Then, solutions A and C are mixed in equal quantities to form the final solution, which has 12.5% milk.

Step 2: Milk percentage in Solution C

When A and B are mixed in the ratio of 3:2, the milk content in Solution C can be calculated using the weighted average formula for mixtures:

Milk percentage in C=3×10%+2×X%3+2\text{Milk percentage in C} = \frac{3 \times 10\% + 2 \times X\%}{3 + 2}

Simplifying this expression:

Milk percentage in C=30+2X5=6+2X5\text{Milk percentage in C} = \frac{30 + 2X}{5} = 6 + \frac{2X}{5}

Thus, the milk percentage in Solution C is 6+2X56 + \frac{2X}{5}.

Step 3: Milk percentage in the final mixture

Now, Solution A and Solution C are mixed in equal quantities to form the final solution, which has 12.5% milk. Since they are mixed in equal amounts, the milk percentage in the final solution is the simple average of the milk percentages in Solution A and Solution C:

10%+(6+2X5)2=12.5%\frac{10\% + \left(6 + \frac{2X}{5}\right)}{2} = 12.5\%

Step 4: Set up the equation

We can now set up the equation:

10+(6+2X5)2=12.5\frac{10 + \left(6 + \frac{2X}{5}\right)}{2} = 12.5

Multiply both sides of the equation by 2 to eliminate the denominator:

10+6+2X5=2510 + 6 + \frac{2X}{5} = 25

Simplify:

16+2X5=2516 + \frac{2X}{5} = 25

Subtract 16 from both sides:

2X5=9\frac{2X}{5} = 9

Step 5: Solve for XX

Multiply both sides by 5:

2X=452X = 45

Now divide by 2:

X=22.5X = 22.5

Thus, the percentage of milk in Solution B is 22.5%\boxed{22.5\%}.


Would you like more details or have any questions?

Related questions:

  1. How do you calculate the weighted average in mixtures?
  2. What would the final percentage of milk be if Solution B had 25% milk instead of 22.5%?
  3. How does changing the mixing ratio of solutions A and B affect the final mixture?
  4. What if solutions A and B were mixed in a ratio of 2:3 instead? How would the answer change?
  5. Can the formula for weighted averages be used for other substances, like sugar in water?

Tip:

Always ensure that ratios are applied correctly when mixing solutions to get accurate results in percentage calculations.

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Mixture Problems
Weighted Average
Algebra

Formulas

Milk percentage in C = (3 * 10% + 2 * X%) / (3 + 2)
Final milk percentage = (Milk percentage in A + Milk percentage in C) / 2

Theorems

Weighted Average Theorem

Suitable Grade Level

Grades 9-12