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The problem asks for the range where 68% of pregnancies will fall, given that the lengths of pregnancies are normally distributed with a **mean of 270 days** and a **standard deviation of 14 days**.

In a normal distribution, the middle 68% corresponds to one standard deviation from the mean, both above and below. This means the range will be between:

\[
\text{Lower Bound} = \mu - \sigma
\]
\[
\text{Upper Bound} = \mu + \sigma
\]

Where:
- \(\mu = 270\) days (mean),
- \(\sigma = 14\) days (standard deviation).

Let's calculate these values.

\[
\text{Lower Bound} = 270 - 14 = 256
\]
\[
\text{Upper Bound} = 270 + 14 = 284
\]

Thus, the middle 68% of pregnancy lengths should fall between **256 days** and **284 days**.

Would you like further clarification on this or a more detailed breakdown?

Here are some related questions:
1. What is the 95% range for pregnancy lengths given the same distribution?
2. How is the percentage distribution divided in a normal curve?
3. How do you calculate the probability for non-standard intervals?
4. How would the answer change if the standard deviation was larger?
5. What does it mean for data to be "normally distributed"?

**Tip:** The middle 68% in a normal distribution always corresponds to ±1 standard deviation from the mean.

The lengths of pregnancies in a small rural village are normally distributed with a mean of 270 days and a standard deviation of 14 days. In what range would we expect to find the middle 68% of most lengths of pregnancies? Round the answer to one decimal place.

Learn how to calculate the range for the middle 68% of pregnancy lengths in a normally distributed data set with a mean of 270 days and a standard deviation of 14 days. This step-by-step guide is perfect for Grades 10-12 statistics students.

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