Math Problem Statement

Find the median of the following: x 10-20 20-30 30-40 40-50 50-60 60-70 70-80 frequency 12 30 34 65 45 5 18\

Solution

To find the median of a frequency distribution, we first need to follow these steps:

Steps to Calculate the Median:

  1. Identify the cumulative frequency to locate the median class.
  2. Determine the total number of observations.
  3. Find the median class.
  4. Use the formula for the median for grouped data.

Step 1: Create a cumulative frequency table.

Class IntervalFrequency (f)Cumulative Frequency (CF)
10-201212
20-303012 + 30 = 42
30-403442 + 34 = 76
40-506576 + 65 = 141
50-6045141 + 45 = 186
60-705186 + 5 = 191
70-8018191 + 18 = 209

Step 2: Calculate the total number of observations.

The total number of observations, N=209N = 209.

Step 3: Find the median class.

The median is located at the N2\frac{N}{2}-th observation. So, 2092=104.5\frac{209}{2} = 104.5. The cumulative frequency just greater than 104.5 is 141, which corresponds to the class interval 40-50. This is the median class.

Step 4: Apply the median formula for grouped data.

The formula for the median is:

Median=L+(N2CFf)×h\text{Median} = L + \left(\frac{\frac{N}{2} - CF}{f}\right) \times h

Where:

  • L=40L = 40 (lower boundary of the median class),
  • N2=104.5\frac{N}{2} = 104.5,
  • CF=76CF = 76 (cumulative frequency of the class preceding the median class),
  • f=65f = 65 (frequency of the median class),
  • h=10h = 10 (class width).

Now, substitute the values into the formula:

Median=40+(104.57665)×10\text{Median} = 40 + \left(\frac{104.5 - 76}{65}\right) \times 10 Median=40+(28.565)×10\text{Median} = 40 + \left(\frac{28.5}{65}\right) \times 10 Median=40+(0.4385)×10\text{Median} = 40 + (0.4385) \times 10 Median=40+4.385\text{Median} = 40 + 4.385 Median44.39\text{Median} \approx 44.39

Final Answer:

The median of the data is approximately 44.39.

Would you like more details on this process or have any questions?

Here are 5 questions related to the concept of finding the median:

  1. How is the cumulative frequency table constructed?
  2. What is the difference between grouped and ungrouped data when finding the median?
  3. Can the median class change if the frequency distribution is adjusted slightly?
  4. Why do we use the lower boundary of the median class in the formula?
  5. How would the median be affected if we increased the class width?

Tip: Always ensure you identify the median class correctly by checking the cumulative frequencies carefully.

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Math Problem Analysis

Mathematical Concepts

Statistics
Median
Cumulative Frequency
Grouped Data

Formulas

Median = L + ((N/2 - CF) / f) * h

Theorems

Median Formula for Grouped Data

Suitable Grade Level

Grades 9-12