Math Problem Statement
Solution
The given problem involves determining the local maximum of the function:
To find the local maximum value, we proceed as follows:
Step 1: Analyze the function
The function is the product of two absolute values, raised to the powers and :
- : This term is zero at , increases as increases, and is symmetric about .
- : This term is zero at , increases as moves away from , and is asymmetric.
The combined behavior creates a local maximum at some point between and , where the product achieves a balance between the two terms.
Step 2: Rewrite
Let be in . The absolute values simplify to:
Step 3: Find the critical points
To find the critical points, compute the derivative : Using the product rule:
Set :
Simplify by dividing through by (valid since ):
Rearrange to solve for :
Step 4: Compute at
Substitute into :
Simplify :
Thus:
Step 5: Final Expression for the Local Maximum
The local maximum value is:
Step 6: Correct Answer
From the given options, the correct answer is:
(d) .
Let me know if you'd like further clarification or detailed steps!
Related Questions:
- What is the derivative of for general ?
- How do you find the critical points of a product of functions?
- How does the symmetry of and affect the behavior of functions?
- Can you derive the second derivative of to confirm the local maximum at ?
- How does the value of and affect the location and value of the maximum?
Tip:
When dealing with products of terms involving absolute values, carefully simplify their behavior in different regions of and use symmetry to reduce the complexity of calculations.
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Math Problem Analysis
Mathematical Concepts
Critical points of functions
Maximization of functions
Absolute values and exponents
Derivative and optimization
Formulas
f(x) = x^m (1 - x)^n
f'(x) = m x^(m-1) (1 - x)^n - n x^m (1 - x)^(n-1)
Local maximum value: f_max = (m^m n^n) / (m+n)^(m+n)
Theorems
Critical point theorem for maxima and minima
Power rule for derivatives
Product rule for derivatives
Suitable Grade Level
Grades 11-12