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Let's solve this problem step by step.

We are given:

- The bank loaned out **$17,000** in total.
- Part of it was loaned at an interest rate of **6%** per year.
- The rest was loaned at **16%** per year.
- The total interest earned in one year was **$1,500**.

We need to find how much of the $17,000 was loaned out at **6%**.

### Step 1: Define the variables
Let:
- $ x $ = amount loaned at 6% (what we need to find).
- $ 17,000 - x $ = amount loaned at 16% (the rest of the money).

### Step 2: Set up the equation for total interest
The total interest earned is from both parts of the loan:
- Interest from the 6% loan: $ 0.06x $.
- Interest from the 16% loan: $ 0.16(17,000 - x) $.

The total interest from both loans is given as $1,500. So, the equation is:
\[
0.06x + 0.16(17,000 - x) = 1,500
\]

### Step 3: Solve the equation
First, distribute the 0.16 on the right side:
\[
0.06x + 0.16(17,000) - 0.16x = 1,500
\]
\[
0.06x + 2,720 - 0.16x = 1,500
\]

Combine like terms:
\[
-0.10x + 2,720 = 1,500
\]

Subtract 2,720 from both sides:
\[
-0.10x = 1,500 - 2,720
\]
\[
-0.10x = -1,220
\]

Divide both sides by -0.10:
\[
x = \frac{-1,220}{-0.10} = 12,200
\]

So, **$12,200** was loaned at 6%.

Would you like more details on this solution, or have any specific questions?

Here are 5 related questions to explore:

1. How much interest was earned from the portion loaned at 6%?
2. How much of the $17,000 was loaned at 16%?
3. What would the total interest be if the entire amount had been loaned at 6%?
4. What would the interest be if the entire amount had been loaned at 16%?
5. If the interest rates change, how would that affect the total interest earned?

**Tip:** For problems involving interest, always set up an equation by expressing the interest for each part of the loan and then equate it to the total interest.

A bank loaned out $17,000, part of it at the rate of 6% per year and the rest at 16% per year. If the interest received in one year totaled $1,500, how much was loaned at 6%?

Learn how to determine how much of a $17,000 loan was borrowed at 6% when the total interest earned is $1,500. This problem covers algebraic concepts including linear equations and solving for unknowns, suitable for students in Grades 9-11.

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