Math Problem Statement

The perimeter of a​ rectangular-shaped field is 116 ft. The width is 24 ft shorter than the length. Find the length and width of the field. Question content area bottom Part 1 Read​ carefully, and assign variables. Part 2 Let xequalsthe length ​(in feet), and yequalsthe width​ (in feet). Part 3 Write two equations. First complete the sentence that describes the formula for the perimeter of a rectangle. Perimeter of a rectangle equals twice the length plus twice the width. Part 4 Use the above formula and the assigned​ variables, x and​ y, to write an equation.    enter your response hereplus2y equals    enter your response here ​(1)

Solution

Let's break the problem down step by step.

Part 1: Assign Variables

  • Let xx represent the length of the field (in feet).
  • Let yy represent the width of the field (in feet).

Part 2: Understanding the Perimeter Formula

The formula for the perimeter PP of a rectangle is: P=2x+2yP = 2x + 2y Where:

  • xx is the length.
  • yy is the width.

Part 3: Given Information

  • The perimeter is 116 feet, so: 116=2x+2y116 = 2x + 2y
  • The width is 24 feet shorter than the length, so: y=x24y = x - 24

Part 4: Write Two Equations

Using the perimeter formula and the relationship between the length and width, we can write the following system of equations:

  1. Perimeter equation: 2x+2y=1162x + 2y = 116
  2. Width equation (from the given information): y=x24y = x - 24

Now, let's substitute the second equation into the first equation.

Step 1: Substitute y=x24y = x - 24 into the perimeter equation:

2x+2(x24)=1162x + 2(x - 24) = 116

Step 2: Simplify the equation:

2x+2x48=1162x + 2x - 48 = 116 4x48=1164x - 48 = 116

Step 3: Solve for xx:

4x=116+484x = 116 + 48 4x=1644x = 164 x=1644=41x = \frac{164}{4} = 41

So, the length x=41x = 41 feet.

Step 4: Solve for yy:

Now, substitute x=41x = 41 into the second equation y=x24y = x - 24: y=4124=17y = 41 - 24 = 17

Thus, the width y=17y = 17 feet.

Final Answer:

  • Length of the field = 41 feet
  • Width of the field = 17 feet

Would you like further details or assistance with another problem?


Here are some related questions that may help expand your understanding:

  1. How would you solve for the perimeter if the length and width were given as different expressions (e.g., x+2y=130x + 2y = 130)?
  2. What would happen to the perimeter if the width were increased by 10 feet?
  3. How can you derive the perimeter formula using algebraic expressions for a rectangle?
  4. How can the equation system be solved by substitution instead of elimination?
  5. Can you generalize the solution method for other geometric shapes?

Tip: When working with word problems involving geometric shapes, always write down the formulas first and identify the relationships between the given quantities. This will help you set up the right system of equations.

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Math Problem Analysis

Mathematical Concepts

Algebra
Linear Equations
Geometry

Formulas

Perimeter of a rectangle: P = 2x + 2y

Theorems

Substitution method for solving systems of equations

Suitable Grade Level

Grades 7-9