To solve the problem, let's use the information provided:

1. The perimeter $P$ of the rectangle is 40 m.
2. The length $L$ is 4 m more than three times the width $W$. This can be expressed as: $L = 3W + 4$

The formula for the perimeter of a rectangle is given by: $P = 2L + 2W$ Substituting the given perimeter and the expression for $L$: $40 = 2(3W + 4) + 2W$

Let's solve this equation to find the width $W$ and then find the length $L$.The width $W$ of the rectangle is 4 meters, and the length $L$ is 16 meters.

Would you like further details on any steps or have any other questions? Here are some related questions you might consider:

1. How would the dimensions change if the perimeter were different?
2. What if the length were directly three times the width, without the additional 4 meters?
3. Can you find the area of the rectangle with these dimensions?
4. How would you find the diagonal of the rectangle?
5. What happens to the perimeter if only the width is doubled?

Tip: Always check your solutions by substituting them back into the original equation to ensure they satisfy all given conditions.