Find the least number which is exactly divisible by each one of the numbers 12, 16 and 24.

To find the least number that is exactly divisible by 12, 16, and 24, we need to determine the **Least Common Multiple (LCM)** of these numbers.

### Steps to find the LCM:
1. **Prime factorization** of each number:
   - \( 12 = 2^2 \times 3 \)
   - \( 16 = 2^4 \)
   - \( 24 = 2^3 \times 3 \)

2. **Identify the highest powers** of all prime factors:
   - For \( 2 \): The highest power is \( 2^4 \) (from 16).
   - For \( 3 \): The highest power is \( 3^1 \) (from 12 and 24).

3. **Multiply these highest powers** together to find the LCM:
   \[
   \text{LCM} = 2^4 \times 3^1 = 16 \times 3 = 48
   \]

So, the least number that is exactly divisible by 12, 16, and 24 is **48**.

Would you like further details or have any other questions?

Here are five related questions:
1. What is the LCM of 8, 14, and 21?
2. How do you find the LCM of two numbers using the prime factorization method?
3. What is the greatest common divisor (GCD) of 12, 16, and 24?
4. Can a number be a multiple of 12, 16, and 24 but not the LCM?
5. What is the smallest number divisible by 15, 20, and 30?

**Tip:** The LCM of a set of numbers is the smallest number that all of the numbers divide into without leaving a remainder.

Discover how to find the least number divisible by 12, 16, and 24 using the Least Common Multiple (LCM) method. Learn step-by-step with prime factorization and highest powers. Suitable for students in Grades 6-8.

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