Math Problem Statement

Find JK where JM = 3x + 15 and MK = 8x + 25 on a straight line.

Solution

To solve for JKJK, we need to use the fact that the line \ell is a straight line, which implies that the sum of the distances on either side of point MM should be equal to the entire segment JKJK. The expressions for the distances are given as follows:

  • JM=3x+15JM = 3x + 15
  • MK=8x+25MK = 8x + 25

Since JKJK is a straight line, we have the equation:

JM+MK=JKJM + MK = JK

Substituting the expressions for JMJM and MKMK, we get:

(3x+15)+(8x+25)=JK(3x + 15) + (8x + 25) = JK

Simplifying the left-hand side:

3x+15+8x+25=JK3x + 15 + 8x + 25 = JK

11x+40=JK11x + 40 = JK

Now, to find the value of JKJK, we would need to determine xx. However, if no further conditions are provided, JKJK will remain expressed as 11x+4011x + 40.

Do you have additional information for solving xx, or should we leave JKJK in terms of xx? Let me know if you want further details on any part of this!

Related Questions:

  1. How do we find xx if additional constraints are provided?
  2. What are the properties of line segments and how are they applied in geometry problems?
  3. How can we check if two segments are congruent using algebraic expressions?
  4. What is the concept of partitioning a line in terms of segments?
  5. How do parallel lines affect the relationships of angles and distances?

Tip:

Always check if the problem contains geometric properties like congruence, parallelism, or additional relationships that can help determine unknown variables.

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Math Problem Analysis

Mathematical Concepts

Algebra
Linear Equations
Geometry

Formulas

Sum of segments: JM + MK = JK

Theorems

Segment Addition Postulate

Suitable Grade Level

Grades 7-9