It looks like there might be a typo in the equation you've provided, as it appears to repeat itself. I'll assume you meant to write the equation as $-x - 3y = 18$. If that's correct, I can help you find the intercepts.

1. Finding the x-intercept:

To find the x-intercept, set $y = 0$ in the equation and solve for $x$:

$-x - 3(0) = 18$

$-x = 18 \quad \Rightarrow \quad x = -18$

So, the x-intercept is $(-18, 0)$.

2. Finding the y-intercept:

To find the y-intercept, set $x = 0$ in the equation and solve for $y$:

$-(0) - 3y = 18$

$-3y = 18 \quad \Rightarrow \quad y = -6$

So, the y-intercept is $(0, -6)$.

Final Answer:

• The x-intercept is $(-18, 0)$.
• The y-intercept is $(0, -6)$.

Would you like a detailed explanation of how these intercepts were found or have any other questions?

Here are 5 related questions:

1. How do you find the intercepts of a quadratic equation?
2. What do the intercepts represent in the graph of a function?
3. How would the intercepts change if the equation was $x + 3y = -18$?
4. How can intercepts be used to graph a linear equation?
5. What is the significance of the slope in a linear equation like this?

Tip: When finding intercepts, remember to set the other variable to zero and solve for the remaining variable.