Math Problem Statement

Find the hypotenuse of the right-angled triangle △NZP, given that NZ = 8 and ZP = 15.

Solution

The given image shows a right-angled triangle △NZP, where:

  • NZ = 8 (one leg)
  • ZP = 15 (other leg)
  • NP = x (hypotenuse, to be found)

We can use the Pythagorean theorem:

NP2=NZ2+ZP2NP^2 = NZ^2 + ZP^2

Substituting the given values:

x2=82+152x^2 = 8^2 + 15^2

x2=64+225x^2 = 64 + 225

x2=289x^2 = 289

x=289x = \sqrt{289}

x=17x = 17

Final Answer:

x=17\mathbf{x = 17}

Would you like a detailed step-by-step explanation?

Here are 5 related questions to expand your understanding:

  1. How do you apply the Pythagorean theorem to different right-angled triangles?
  2. What are Pythagorean triplets, and is (8, 15, 17) a Pythagorean triplet?
  3. How do you calculate the area of a right-angled triangle given two sides?
  4. What is the sine, cosine, and tangent of angle N in this triangle?
  5. How do you find the missing leg if the hypotenuse and one leg are known?

Tip: The Pythagorean theorem only works for right-angled triangles! Always check the given angles before applying it.

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Math Problem Analysis

Mathematical Concepts

Geometry
Right-Angled Triangles
Pythagorean Theorem

Formulas

Pythagorean Theorem: c^2 = a^2 + b^2

Theorems

Pythagorean Theorem

Suitable Grade Level

Grades 7-10