Math Problem Statement

Find the hypotenuse (NΠ) of a right-angled triangle where NP = 15 and ΠP = 25.

Solution

The image you uploaded shows a right-angled triangle with vertices labeled N, P, and Π (Pi). The right angle is at point N. The side lengths are given as:

  • NP (the vertical side) = 15 units
  • ΠP (the horizontal side) = 25 units
  • (the hypotenuse) = X units, which we need to solve for.

This is a typical problem that can be solved using the Pythagorean theorem, which states:

a2+b2=c2a^2 + b^2 = c^2

Where:

  • aa and bb are the legs of the right triangle, and
  • cc is the hypotenuse.

In this case:

  • a=15a = 15,
  • b=25b = 25,
  • c=Xc = X.

We can now plug these values into the Pythagorean theorem to find XX:

152+252=X215^2 + 25^2 = X^2

Let me calculate this for you. math

Given values

a = 15 b = 25

Applying the Pythagorean theorem

X = math.sqrt(a2 + b2) XThe length of the hypotenuse NΠ is approximately 29.15 units.

Would you like further explanation on the Pythagorean theorem or have any other questions?

Here are some related questions:

  1. How do you use the Pythagorean theorem for non-integer side lengths?
  2. What is the difference between the Pythagorean theorem and the distance formula?
  3. Can the Pythagorean theorem be applied to 3D geometry?
  4. How do you determine if a triangle is a right triangle from its side lengths?
  5. How can trigonometry be used to find angles in right triangles?

Tip: Always check if the triangle is a right triangle before applying the Pythagorean theorem!

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Math Problem Analysis

Mathematical Concepts

Geometry
Right-Angled Triangles
Pythagorean Theorem

Formulas

a² + b² = c²

Theorems

Pythagorean Theorem

Suitable Grade Level

Grades 7-10