Math Problem Statement

Work out the value of x in a right-angled triangle with sides 9 cm and 7 cm, and hypotenuse x. Give your answer correct to 1 decimal place.

Solution

This is a right-angled triangle problem where we need to find the hypotenuse xx using the Pythagorean Theorem:

a2+b2=c2a^2 + b^2 = c^2

where:

  • a=7a = 7 cm
  • b=9b = 9 cm
  • c=xc = x (hypotenuse)

Step 1: Substitute values

72+92=x27^2 + 9^2 = x^2

49+81=x249 + 81 = x^2

130=x2130 = x^2

Step 2: Solve for xx

x=130x = \sqrt{130}

x11.4 cm(rounded to 1 decimal place)x \approx 11.4 \text{ cm} \quad \text{(rounded to 1 decimal place)}

Final Answer:

x=11.4 cmx = 11.4 \text{ cm}

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Related Questions:

  1. How do you identify the hypotenuse in a right-angled triangle?

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Math Problem Analysis

Mathematical Concepts

Geometry
Right-Angled Triangles
Pythagorean Theorem

Formulas

a² + b² = c²

Theorems

Pythagorean Theorem

Suitable Grade Level

Grades 7-9