Harley the horse trots down the street with an acceleration of -3m/s2.  Harley trots for 4.31 seconds until she reaches a crosswalk and stops.   What was Harley’s initial velocity?

To find Harley’s initial velocity, we can use the kinematic equation:

\[
v_f = v_i + a t
\]

Where:
- \( v_f \) is the final velocity,
- \( v_i \) is the initial velocity,
- \( a \) is the acceleration, and
- \( t \) is the time.

Given:
- \( v_f = 0 \, \text{m/s} \) (Harley stops),
- \( a = -3 \, \text{m/s}^2 \),
- \( t = 4.31 \, \text{seconds} \).

Now, solve for \( v_i \):

\[
0 = v_i + (-3)(4.31)
\]
\[
v_i = 3 \times 4.31
\]
\[
v_i = 12.93 \, \text{m/s}
\]

So, Harley’s initial velocity was **12.93 m/s**.

Would you like a deeper explanation, or have any questions?

Here are 5 related questions to explore:
1. How far did Harley travel during the 4.31 seconds?
2. What would Harley’s velocity be if the acceleration were \( -2 \, \text{m/s}^2 \)?
3. How long would it take Harley to stop if the initial velocity was 15 m/s?
4. What is the significance of a negative acceleration?
5. How would the situation change if Harley’s acceleration was positive?

**Tip:** A negative acceleration means that an object is slowing down if it's moving in the positive direction.

Harley the horse trots down the street with an acceleration of -3m/s^2. Harley trots for 4.31 seconds until she reaches a crosswalk and stops. What was Harley’s initial velocity?

Discover how to calculate Harley’s initial velocity given an acceleration of -3 m/s^2 and a time of 4.31 seconds using kinematic equations. This problem explores linear motion concepts and is suitable for students in Grades 9-12.

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