A powerful motorcycle can accelerate from rest to 26 m/s in only 3.2s. How far does it travel in that time? (Express the numeral of your answer in SI units)

The motorcycle travels **41.6** meters in 3.2 seconds.

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Here are 5 related questions to consider:
1. What is the motorcycle's acceleration in \(\text{m/s}^2\)?
2. How much distance would the motorcycle cover if it accelerated for 5 seconds instead of 3.2 seconds?
3. What would be the final velocity if the motorcycle accelerated for 4 seconds instead of 3.2 seconds?
4. If the initial velocity was 5 m/s instead of 0 m/s, what would be the distance traveled in 3.2 seconds?
5. How much time would it take for the motorcycle to reach a speed of 30 m/s with the same acceleration?

**Tip:** For motion with constant acceleration, remember that the distance covered can be calculated using the kinematic equation \( s = ut + \frac{1}{2}at^2 \), even when initial velocity is zero.

Discover how far a motorcycle travels when accelerating from rest to 26 m/s in 3.2 seconds. This problem involves using the kinematic equation to calculate distance, considering constant acceleration. Suitable for students in Grades 9-12.

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