f(x)=5 and g(x)=5x then g(x)-f(x) is always equal to

Given:
\[
f(x) = 5
\]
\[
g(x) = 5x
\]

To find \( g(x) - f(x) \), we substitute \( f(x) \) and \( g(x) \) as follows:

\[
g(x) - f(x) = 5x - 5
\]

Therefore, \( g(x) - f(x) = 5(x - 1) \).

This expression, \( 5(x - 1) \), depends on the value of \( x \) and is not a constant; it varies with \( x \). So, the answer is:

\[
g(x) - f(x) = 5(x - 1)
\]

Would you like more details or have any questions? 

Here are some related questions for practice:
1. What is \( g(x) + f(x) \) given the same functions?
2. If \( h(x) = g(x) \cdot f(x) \), what is \( h(x) \)?
3. How would the expression \( g(x) - f(x) \) change if \( f(x) = 2 \)?
4. If \( f(x) = 5 \) and \( g(x) = 5x^2 \), what would \( g(x) - f(x) \) equal?
5. How would the expression \( g(x) - f(x) \) simplify if \( x = 1 \)?

**Tip:** When finding \( g(x) - f(x) \), substitute the functions and simplify carefully, watching for constants versus variable terms.

f(x) = 5 and g(x) = 5x then g(x) - f(x) is always equal to

Understand how to find g(x) - f(x) when given f(x) = 5 and g(x) = 5x. This algebra problem includes function operations and demonstrates how expressions vary with x. Suitable for Grades 8-10.

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