Math Problem Statement

find the gradient of side BC

Solution

To find the gradient (or slope) of side BCBC, we use the formula for the slope between two points (x1,y1)(x_1, y_1) and (x2,y2)(x_2, y_2): slope=m=y2y1x2x1\text{slope} = m = \frac{y_2 - y_1}{x_2 - x_1}

Here, the coordinates of points BB and CC are:

  • B(7,6)B(-7, -6)
  • C(7,4)C(7, 4)

Step 1: Apply the slope formula

Substitute the coordinates of BB and CC into the slope formula: m=4(6)7(7)=4+67+7=1014=57m = \frac{4 - (-6)}{7 - (-7)} = \frac{4 + 6}{7 + 7} = \frac{10}{14} = \frac{5}{7}

Final Answer

The gradient (slope) of side BCBC is 57\frac{5}{7}.

Would you like any further explanation on the slope calculation, or do you have any other questions?


Here are some related questions:

  1. How does the slope 57\frac{5}{7} indicate the direction of side BCBC?
  2. What would the slope of side ABAB be, given points AA and BB?
  3. How would the slope change if we reflected the triangle across the y-axis?
  4. Can you find the equation of the line that passes through points BB and CC?
  5. How does the slope of side BCBC compare to the slope of side ACAC?

Tip: The slope provides a quick understanding of the steepness and direction of a line.

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Math Problem Analysis

Mathematical Concepts

Analytic Geometry
Slope of a Line

Formulas

Slope formula

Theorems

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Suitable Grade Level

Grades 9-12