Math Problem Statement

Find 2 geometric means between 7 and 189

Solution

To find two geometric means between 7 and 189, we can follow the process of inserting two numbers in a geometric sequence. Let the four terms of the sequence be:

7,G1,G2,1897, G_1, G_2, 189

Since the numbers form a geometric sequence, the ratio between consecutive terms must be constant. Let that ratio be rr.

Thus, we have the following relations: G1=7r,G2=7r2,189=7r3G_1 = 7r, \quad G_2 = 7r^2, \quad 189 = 7r^3

Now, solve for rr: 189=7r3    r3=1897=27    r=273=3189 = 7r^3 \implies r^3 = \frac{189}{7} = 27 \implies r = \sqrt[3]{27} = 3

Now that we know r=3r = 3, we can find the two geometric means:

G1=7r=7×3=21G_1 = 7r = 7 \times 3 = 21 G2=7r2=7×32=7×9=63G_2 = 7r^2 = 7 \times 3^2 = 7 \times 9 = 63

Thus, the two geometric means between 7 and 189 are 21 and 63.

Would you like further details or have any questions?

Here are five related questions you might find interesting:

  1. How do you find three geometric means between two numbers?
  2. What is the formula for the nn-th term of a geometric sequence?
  3. How do arithmetic means differ from geometric means?
  4. How do you determine the common ratio if three terms are given in a geometric sequence?
  5. Can geometric means be negative?

Tip: In a geometric sequence, the ratio between consecutive terms is constant, and multiplying the first term by the common ratio raised to different powers gives the terms.

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Math Problem Analysis

Mathematical Concepts

Geometric Sequence
Geometric Means
Common Ratio

Formulas

G_1 = 7r
G_2 = 7r^2
r^3 = 27

Theorems

Geometric Sequence Theorem: The ratio between consecutive terms remains constant.

Suitable Grade Level

Grades 9-10