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The problem asks how many four-digit natural numbers can be formed using only the digits 1, 2, 3, and 4, if each of these digits can only be used once.

### Step-by-step solution:

1. **First digit**: Since it is a four-digit number, the first digit can be any of 1, 2, 3, or 4. So, there are 4 possible choices for the first digit.

2. **Second digit**: After choosing the first digit, we are left with 3 digits. So, there are 3 possible choices for the second digit.

3. **Third digit**: Once the first two digits are chosen, 2 digits remain. Therefore, there are 2 choices for the third digit.

4. **Fourth digit**: After choosing the first three digits, only 1 digit is left, so there is 1 choice for the fourth digit.

### Calculation:

\[
4 \times 3 \times 2 \times 1 = 24
\]

So, **24** four-digit natural numbers can be formed using the digits 1, 2, 3, and 4 if each digit is used only once.

Would you like more details on this process or have any questions?

Here are 5 related questions:
1. What if repetition of digits was allowed? How would the answer change?
2. How many three-digit numbers can be formed under the same condition?
3. What if we could use digits 0, 1, 2, 3, and 4 but still no repetition?
4. What if we could form five-digit numbers with digits 1, 2, 3, 4, and 5 without repetition?
5. What is the probability that a randomly chosen four-digit number formed from 1, 2, 3, and 4 is even?

**Tip**: Problems involving permutations like this one often require a good understanding of factorials!

How many four-digit natural numbers can be formed using only the digits 1, 2, 3, and 4, if the numbers can use each of these digits only once?

Discover how to find the number of four-digit natural numbers that can be formed using the digits 1, 2, 3, and 4 without repetition. Understand the use of permutations and factorials to solve this problem, ideal for Grades 6-8 students.

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