A car moving with a velocity of 15�/� has a uniform acceleration of 2�/�(. If it moves for
2.5sec, find it's final velocity. [U]
a.10 �/� b. 15�/� c. 20�/� d. 24�/�

To find the final velocity of the car, we can use the first equation of motion:

\[
v = u + at
\]

where:
- \( v \) is the final velocity,
- \( u = 15 \, \text{m/s} \) is the initial velocity,
- \( a = 2 \, \text{m/s}^2 \) is the uniform acceleration,
- \( t = 2.5 \, \text{seconds} \) is the time.

Now substitute the values:

\[
v = 15 \, \text{m/s} + (2 \, \text{m/s}^2 \times 2.5 \, \text{seconds})
\]
\[
v = 15 \, \text{m/s} + 5 \, \text{m/s}
\]
\[
v = 20 \, \text{m/s}
\]

Thus, the final velocity of the car is \( \mathbf{20 \, \text{m/s}} \).

The correct answer is **c. 20 m/s**.

Would you like more details, or do you have any further questions?

Here are 5 related questions to explore:
1. What would the final velocity be if the acceleration was 3 m/s²?
2. How far does the car travel in the 2.5 seconds?
3. What if the initial velocity was 10 m/s instead?
4. How would the velocity change if the time of travel was 5 seconds?
5. Can you derive the equation for uniform acceleration?

**Tip**: Always ensure you use the right units when calculating velocity and acceleration, as mismatches can lead to incorrect results.

A car moving with a velocity of 15 m/s has a uniform acceleration of 2 m/s². If it moves for 2.5 sec, find its final velocity. a. 10 m/s b. 15 m/s c. 20 m/s d. 24 m/s

Learn how to calculate the final velocity of a car moving with an initial velocity of 15 m/s and a uniform acceleration of 2 m/s² over 2.5 seconds. This problem applies the first equation of motion: v = u + at, suitable for students in Grades 9-10.

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