To find the final velocity of the car, we can use the first equation of motion:

$v = u + at$

where:

• $v$ is the final velocity,
• $u = 15 \, \text{m/s}$ is the initial velocity,
• $a = 2 \, \text{m/s}^2$ is the uniform acceleration,
• $t = 2.5 \, \text{seconds}$ is the time.

Now substitute the values:

$v = 15 \, \text{m/s} + (2 \, \text{m/s}^2 \times 2.5 \, \text{seconds})$ $v = 15 \, \text{m/s} + 5 \, \text{m/s}$ $v = 20 \, \text{m/s}$

Thus, the final velocity of the car is $\mathbf{20 \, \text{m/s}}$.

The correct answer is c. 20 m/s.

Would you like more details, or do you have any further questions?

Here are 5 related questions to explore:

1. What would the final velocity be if the acceleration was 3 m/s²?
2. How far does the car travel in the 2.5 seconds?
3. What if the initial velocity was 10 m/s instead?
4. How would the velocity change if the time of travel was 5 seconds?
5. Can you derive the equation for uniform acceleration?

Tip: Always ensure you use the right units when calculating velocity and acceleration, as mismatches can lead to incorrect results.