A car accelerates from rest at a constant rate of 3 m/s² for 8 seconds. Calculate the car's final velocity.


To calculate the car's final velocity, we can use the equation of motion:

\[
v = u + at
\]

Where:
- \( v \) is the final velocity,
- \( u \) is the initial velocity,
- \( a \) is the acceleration,
- \( t \) is the time.

Given:
- Initial velocity, \( u = 0 \) m/s (since the car starts from rest),
- Acceleration, \( a = 3 \) m/s²,
- Time, \( t = 8 \) seconds.

Now, substituting the values into the equation:

\[
v = 0 + (3 \, \text{m/s}^2) \times 8 \, \text{s} = 24 \, \text{m/s}
\]

So, the car's final velocity is **24 m/s**.

Would you like any details or have any questions?

Here are 5 related questions to expand your understanding:
1. What is the displacement of the car after 8 seconds?
2. How would the final velocity change if the acceleration was doubled?
3. What would be the final velocity if the car started with an initial velocity of 5 m/s?
4. How would the time affect the final velocity if acceleration remained constant?
5. What is the difference between constant and variable acceleration?

**Tip:** Always ensure the units are consistent when using equations of motion, especially in problems involving different physical quantities like time, velocity, and acceleration.

Learn how to calculate the final velocity of a car that accelerates from rest at a constant rate of 3 m/s² for 8 seconds. Understand the key concepts of kinematics and equations of motion. Suitable for students in Grades 9-12.

Math Problem Statement

Solution

Ask a new question for Free

By Image

Math Problem Analysis

Mathematical Concepts

Formulas

Theorems

Suitable Grade Level

Related Recommendation