To calculate the car's final velocity, we can use the equation of motion:

$v = u + at$

Where:

• $v$ is the final velocity,
• $u$ is the initial velocity,
• $a$ is the acceleration,
• $t$ is the time.

Given:

• Initial velocity, $u = 0$ m/s (since the car starts from rest),
• Acceleration, $a = 3$ m/s²,
• Time, $t = 8$ seconds.

Now, substituting the values into the equation:

$v = 0 + (3 \, \text{m/s}^2) \times 8 \, \text{s} = 24 \, \text{m/s}$

So, the car's final velocity is 24 m/s.

Would you like any details or have any questions?

Here are 5 related questions to expand your understanding:

1. What is the displacement of the car after 8 seconds?
2. How would the final velocity change if the acceleration was doubled?
3. What would be the final velocity if the car started with an initial velocity of 5 m/s?
4. How would the time affect the final velocity if acceleration remained constant?
5. What is the difference between constant and variable acceleration?

Tip: Always ensure the units are consistent when using equations of motion, especially in problems involving different physical quantities like time, velocity, and acceleration.