The functions $f(x) = -4x - 3$ and $g(x) = 2x^3 + 6$ are given, and you're asked to find $f(6)$ and $g(-4)$.

Let's solve these:

1. Finding $f(6)$:

Substitute $x = 6$ into $f(x)$: $f(6) = -4(6) - 3 = -24 - 3 = -27$

2. Finding $g(-4)$:

Substitute $x = -4$ into $g(x)$: $g(-4) = 2(-4)^3 + 6 = 2(-64) + 6 = -128 + 6 = -122$

Final answers:

• $f(6) = -27$
• $g(-4) = -122$

Would you like any further details or have any questions?

Here are some related questions:

1. What is $f(0)$ and $g(0)$?
2. Can you explain the behavior of $f(x)$ for large $x$?
3. What is the domain and range of $f(x)$ and $g(x)$?
4. How would $g(x)$ behave as $x \to \infty$?
5. Find the zeros of both $f(x)$ and $g(x)$.

Tip: Always substitute values carefully and simplify step-by-step to avoid errors in calculations!