Let's solve the expression step by step:

Given the functions:

$f(x) = 3x - 3$ $g(x) = -x^2 + 4$

We are asked to find the value of:

$f(2) - g(-2)$

Step 1: Find $f(2)$

To find $f(2)$, substitute $x = 2$ into the function $f(x)$:

$f(2) = 3(2) - 3 = 6 - 3 = 3$

Step 2: Find $g(-2)$

To find $g(-2)$, substitute $x = -2$ into the function $g(x)$:

$g(-2) = -(-2)^2 + 4 = -(4) + 4 = -4 + 4 = 0$

Step 3: Calculate $f(2) - g(-2)$

Now, subtract $g(-2)$ from $f(2)$:

$f(2) - g(-2) = 3 - 0 = 3$

Final Answer:

$f(2) - g(-2) = 3$

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Would you like any further explanation or details on this?

Here are 5 related questions you can explore:

1. What is the composition of the functions $f(x)$ and $g(x)$?
2. How would the value of $f(2) - g(-2)$ change if the functions were modified?
3. How do you evaluate a function at a specific point like $g(-2)$?
4. What is the general method for finding $f(a) - g(b)$ for any functions?
5. How can we graph the functions $f(x)$ and $g(x)$?

Tip: Always remember to plug in the exact values for $x$ in each function and simplify carefully.