Math Problem Statement

Write down an expression for this sequence: -1, 3, 9, 17, 27, 39

Solution

To find an expression for the sequence 1,3,9,17,27,39-1, 3, 9, 17, 27, 39, let's analyze the pattern:

Step 1: Identify the sequence pattern

The sequence appears to be neither purely arithmetic nor geometric, so let's look at the differences between the terms:

  • 3(1)=43 - (-1) = 4
  • 93=69 - 3 = 6
  • 179=817 - 9 = 8
  • 2717=1027 - 17 = 10
  • 3927=1239 - 27 = 12

The differences between consecutive terms are 4,6,8,10,124, 6, 8, 10, 12, which form an arithmetic sequence with a common difference of 22.

Step 2: Formulate the general term expression

Given that the first differences themselves form an arithmetic sequence, we can express this sequence as a quadratic sequence of the form:

an=an2+bn+ca_n = an^2 + bn + c

where nn represents the position of the term in the sequence.

Step 3: Set up equations to solve for aa, bb, and cc

Using the first three terms, we set up equations:

For n=1n = 1, a1=1a_1 = -1: a(1)2+b(1)+c=1(Equation 1)a(1)^2 + b(1) + c = -1 \quad \text{(Equation 1)}

For n=2n = 2, a2=3a_2 = 3: a(2)2+b(2)+c=3(Equation 2)a(2)^2 + b(2) + c = 3 \quad \text{(Equation 2)}

For n=3n = 3, a3=9a_3 = 9: a(3)2+b(3)+c=9(Equation 3)a(3)^2 + b(3) + c = 9 \quad \text{(Equation 3)}

Simplifying the equations:

  1. From Equation 1: a+b+c=1a + b + c = -1
  2. From Equation 2: 4a+2b+c=34a + 2b + c = 3
  3. From Equation 3: 9a+3b+c=99a + 3b + c = 9

Step 4: Solve the system of equations

Subtract Equation 1 from Equation 2:

(4a+2b+c)(a+b+c)=3(1)(4a + 2b + c) - (a + b + c) = 3 - (-1)

3a+b=4(Equation 4)3a + b = 4 \quad \text{(Equation 4)}

Subtract Equation 2 from Equation 3:

(9a+3b+c)(4a+2b+c)=93(9a + 3b + c) - (4a + 2b + c) = 9 - 3

5a+b=6(Equation 5)5a + b = 6 \quad \text{(Equation 5)}

Subtract Equation 4 from Equation 5:

(5a+b)(3a+b)=64(5a + b) - (3a + b) = 6 - 4

2a=2    a=12a = 2 \implies a = 1

Substituting a=1a = 1 into Equation 4:

3(1)+b=4    b=13(1) + b = 4 \implies b = 1

Substituting a=1a = 1 and b=1b = 1 into Equation 1:

1+1+c=1    c=31 + 1 + c = -1 \implies c = -3

Step 5: General term formula

Thus, the expression for the nn-th term of the sequence is:

an=n2+n3a_n = n^2 + n - 3

Would you like more details or have any specific questions? Here are some related questions to expand on this topic:

  1. How can you verify if a sequence is quadratic?
  2. What are some other methods to find the general term of a sequence?
  3. How does this quadratic sequence compare to an arithmetic or geometric sequence?
  4. Can you find the sum of the first nn terms of this sequence?
  5. How do the first differences of a quadratic sequence form an arithmetic sequence?

Tip: When dealing with sequences that are neither arithmetic nor geometric, check if the differences between terms form a recognizable pattern, such as a second sequence being arithmetic, which indicates a quadratic relationship!

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Sequences
Quadratic Sequences

Formulas

Quadratic sequence general term formula

Theorems

-

Suitable Grade Level

Grades 9-12