Let's go step by step to solve the given circuit.

1. Equivalent Resistance (Req) of R1 in parallel with R2:

Given:

• $R_1 = 10 \, \text{k}\Omega$
• $R_2 = 100 \, \text{k}\Omega$

For resistors in parallel, the equivalent resistance ($R_{eq}$) is calculated by:

$\frac{1}{R_{eq}} = \frac{1}{R_1} + \frac{1}{R_2}$

Substituting the values:

$\frac{1}{R_{eq}} = \frac{1}{10,000} + \frac{1}{100,000}$

Let's calculate $R_{eq}$.

2. Current $I_1$:

Once we calculate $R_{eq}$, we can find the total current $I_1$ using the following formula:

$I_1 = \frac{V}{R_3 + R_{eq}}$

Where:

• $V = 5 \, \text{V}$
• $R_3 = 10 \, \text{k}\Omega$

3. Voltage Drop over $R_1$:

The voltage drop over $R_1$ can be found using Ohm's Law:

$V_{R1} = I_{R1} \cdot R_1$

4. Voltage Drop over $R_2$:

Since $R_1$ and $R_2$ are in parallel, the voltage across $R_2$ will be the same as that across $R_1$:

$V_{R2} = V_{R1}$

5. Voltage Drop over $R_3$:

The voltage drop across $R_3$ is given by:

$V_{R3} = I_1 \cdot R_3$

6. Current through $R_1$:

Once we have the voltage drop over $R_1$, we can calculate the current through $R_1$ using:

$I_{R1} = \frac{V_{R1}}{R_1}$

7. Current through $R_2$:

Similarly, the current through $R_2$ is:

$I_{R2} = \frac{V_{R2}}{R_2}$

8. Current through $R_3$:

This is the same as $I_1$, which is the total current flowing through the circuit.

Let me now calculate the values for these steps.Here are the calculated results for the circuit:

1. Equivalent Resistance (Req) of $R_1$ and $R_2$ in parallel:
   $R_{eq} = 9090.91 \, \Omega$

2. Total Current $I_1$:
   $I_1 = 0.2619 \, \text{mA}$

3. Voltage Drop over $R_1$:
   $V_{R1} = 2.381 \, \text{V}$

4. Voltage Drop over $R_2$ (same as $R_1$ since they are in parallel):
   $V_{R2} = 2.381 \, \text{V}$

5. Voltage Drop over $R_3$:
   $V_{R3} = 2.619 \, \text{V}$

6. Current through $R_1$:
   $I_{R1} = 0.2381 \, \text{mA}$

7. Current through $R_2$:
   $I_{R2} = 0.0238 \, \text{mA}$

8. Current through $R_3$ (same as $I_1$):
   $I_{R3} = 0.2619 \, \text{mA}$

Do you have any questions or want further details?

Here are some related questions you could explore:

1. How would the total current change if $R_1$ was increased?
2. What would happen if $R_2$ was removed from the circuit?
3. How can the power dissipated in each resistor be calculated?
4. What is the role of $R_3$ in this circuit?
5. How do different resistor configurations (series vs parallel) affect current distribution?

Tip: To simplify parallel resistor networks, always apply the reciprocal rule for resistors in parallel.